Fibonacci

Representation of numbers (part 2)
We now know that each positive integer can be written as a sum of different Fibonacci numbers.
The numbers F1 and F2 were considered as being different, although they have the same numerical value 1.
This leads us to the following question: Suppose we cancel one element from the sequence of Fibonacci numbers (e.g. the number F2). Is it
possible to represent each positive number as a sum of the remaining Fibonacci numbers?
This question will now be answered. We assume that Fn has been canceled (n>1).
If for certain k>n each number less than Fk has a
representation without term Fn, then that will also be true for
each number less than Fk+1 (Add Fk to the
representations for 0,1,2,...,Fk-1-1), and therefore also for all
numbers less than Fk+2 et cetera.
As we already know, all numbers less than Fn+1
are representable with different terms from F1,...,Fn-1.
So, we may choose k=n+1. This completes the proofs.
Deleting two terms in the Fibonacciseries is not allowed, because if we delete
e.g. Fa and Fn with a<n, then
(F1+F2+...+Fn)
- Fn - Fa =
Fn+2 - 1 - Fn - Fa =
Fn+1 - 1 - Fa < Fn+1-1.
So Fn+1-1 is not representable.
